2y^2-4y=-2

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Solution for 2y^2-4y=-2 equation: 



2y^2-4y=-2

We move all terms to the left:

2y^2-4y-(-2)=0

We add all the numbers together, and all the variables

2y^2-4y+2=0

a = 2; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·2·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{4}{4}=1$

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